A solution containing 0.11MPb^(2+),1.5times 10^(-6)MPb^(4+),1.5times 10^(-6)MMn^(+),0.11MMnO_(4)^(-) , and 0.80MHNO_(3) was prepared. For this solution, the balanced reduction half-reactions and overall net reaction shown can occur. 5[Pb^(4+)+2e^(-)⇌Pb^(2+)] E_(+)=1.690V (2[MnO_(4)^(-)+8H^(+)+5e^(-)⇌Mn^(2+)+4H_(2)O])/(5Pb^(4+)+2Mn^(2+)+8H_(2)O⇌5Pb^(2+)+2MnO_(4)^(-)+16H^(+)) E_(-)=1.507V Determine E_(cell ),Delta G, and K for this reaction. E Delta GK= Calculate the value for the cell potential, E_(cell ) , and the free energy, Delta G , for the given conditions.
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[Verified Answer]: A solution containing 0