In a very rare case, Jennifer gets an infection and is put on vancomycin 1000 mg Q12h starting at 8am. At the end of the 5th dose at 7:30 PM, a blood sample is obtained and the concentration is 9.5 m(g)/(L). The dose is administered at 8 PM and is infused for one-hour. At 10 PM, another blood sample is obtained and the concentration is 24.6 m(g)/(L). You are asked to estimate K in this patient. What time value would you use with the two concentrations given in order to estimate K? K = ln (24.6 m(g)/(L)()/() 9.5 m(g)/(L)) ()/() ? In a very rare case, Jennifer gets an infection and is put on vancomycin 1000 mg Q12h starting at 8 am . At the end of the 5^(th ) dose at 7:30 PM, a blood sample is obtained and the concentration is 9.5m(g)/(L). The dose is administered at 8 PM and is infused for one-hour. At 10 PM , another blood sample is obtained and the concentration is 24.6m(g)/(L). You are asked to estimate K in this patient. What time value would you use with the two concentrations given in order to estimate K? K=ln(24.6m(g)/(L)()/(9.5m)(g)/(L))/() ? A. 2.5 h B. 12 h C. 11 h D. 9.5 h
[Verified Answer]: In a very rare case, Jennifer gets an…
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